On 6/5/2013 3:37 PM, Steven Schveighoffer wrote:
No, I think it introduces a new foo. Calling A.foo does not call B.foo. In other words, it hides the original implementation, there are two vtable entries for foo.At least, that is how I understood the C# description from that post, and it seems Walter is trying to specify that. The idea is that B probably defined foo before A did, and A adding foo should not break B, B didn't even know about A's foo.
That's right.
