On Thu, Sep 12, 2013 at 03:17:06AM +0200, Brian Schott wrote: > On Thursday, 12 September 2013 at 00:13:36 UTC, H. S. Teoh wrote: > >But then the code example proceeds to pass byLine() to it. Is that > >correct? If it is, then the docs need to be updated, because last > >time I checked, byLine() isn't a range of char, but a range of char > >*arrays*. > > > > > >T > > The example doesn't pass the result of byLine to the byToken function > directly.
*facepalm* You're right, it's calling join() on it. Nevermind what I said then. :-P Sorry for all the unnecessary noise, I don't know what got into me that I didn't see the join(). T -- May you live all the days of your life. -- Jonathan Swift