Michel Fortin wrote:
Le 28-juin-2013 à 17:03, Rainer Schuetze <r.sagita...@gmx.de> a écrit :
> Any parameter of type C is also lowered to shared_ptr!C.
class C {}
People still constantly forget that C used as a type represents a *reference* to
an object of class C, not the object itself. If you replace type C with
shared_ptr!C, you must then replace it with shared_ptr!(shared_ptr!C) and so on;
there's no end to it.
Also, I strongly doubt the compiler will be able to elide redundant calls to
retain/release made within shared_ptr!C while still respecting normal struct
semantics.
