Jarrett Billingsley wrote:
On Wed, Aug 26, 2009 at 8:47 PM, Stewart Gordon<[email protected]> wrote:
<snip>
Not quite. For example, is
qwert * yuiop;
a declaration of yuiop as a pointer to a qwert, or an instruction to
multiply qwert by yuiop but do nothing with the result?
It's grammatically ambiguous, but not semantically. No-op statements
are illegal.
In D, but not in C or C++.
Thus, it's perfectly fine to always parse this as a
pointer decl, since the other possible parse tree is always
semantically invalid.
As D does.
Stewart.
