Am 24.03.2015 um 21:19 schrieb Steven Schveighoffer:
On 3/24/15 4:11 PM, Andrei Alexandrescu wrote:
On 3/24/15 11:56 AM, "Jacques =?UTF-8?B?TcO8bGxlciI=?=
<jacques.muel...@gmx.de>" wrote:
On Tuesday, 24 March 2015 at 13:09:21 UTC, Steven Schveighoffer wrote:
New code:

immutable nfields = header.count('\t');
...
output.writeln(cycle("\t-").take(2 * nfields));

output.writeln("\t-".repeat(nfields).join);

output.writeln("\t-".repeat(nfields).joiner);


Yeah, I looked at repeat first, but it didn't do what I wanted (would
only repeat a single element).

For some reason, this seems more complex to me. However, it does have
the benefit of not needing the '2 *'. But I did not think of using
joiner, nice solution!

-Steve

Also, the shortest solution:

import std.array;
output.writeln("\t-".replicate(nfields));

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