On Thursday, 1 October 2015 at 01:32:17 UTC, bitwise wrote:
I don't think it would be that hard to make something this possible:

for(int x : iota<int>(0, 5).to<take>(3))
    printf("%d ", x);


Curiosity got the best of me:
http://ideone.com/RoJxLa

output doesn't show up for some reason, but it works.

    Bit


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