On 12/06/2015 03:47 AM, BLM768 wrote:
log(x^2) should approach log(x) as x approaches infinity, I think. (My calculus is a bit rusty.)
log(x^2) = 2 log x.
On 12/06/2015 03:47 AM, BLM768 wrote:
log(x^2) should approach log(x) as x approaches infinity, I think. (My calculus is a bit rusty.)
log(x^2) = 2 log x.