Here is an interesting talk from Naughty Dog
http://www.gdcvault.com/play/1022186/Parallelizing-the-Naughty-Dog-Engine
They move Fibers between threads.
A rough overview:
You create task A that depends on task B. The task is submitted
as a fiber and executed by a thread. Now task A has to wait for
task B to finish so you hold the fiber and put it into a queue,
you also create an atomic counter that tracks all dependencies,
once the counter reaches 0 you know that all dependencies have
finished.
Now you put task A into a queue and execute a different task.
Once a thread completes a task it looks into the queue and checks
if there is one task that has a counter of 0, which means it can
continue to execute that task.
Now move that fiber/task onto a free thread and you can continue
to execute that fiber.
What is the current state of fibers in D? I have asked this
question on SO
https://stackoverflow.com/questions/36663720/how-to-pass-a-fiber-to-a-thread
