On 7/28/2016 1:33 AM, Ethan Watson wrote:
1) Declaring a function pointer with a ref return value can't be done without
workarounds.
Try compiling this:
ref int function( int, int ) functionPointer;
It won't let you, because only parameters and for loop symbols can be ref types.
Despite the fact that I intend the function pointer to be of a kind that returns
a ref int, I can't declare that easily. Easy, declare an alias, right?
alias RefFunctionPointer = ref int function( int, int );
C/C++ have essentially the same problem, if you want to declare a function
pointer parameter that has different linkage.
The trouble is there's an ambiguity in the grammar. I don't really have anything
better than the two step process you outlined.
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4) Forward declaring a function prototype means I can never declare that
function elsewhere (say, for example, with a mixin)
Do you mean:
void foo();
void foo() { }
?
