On 12/14/2016 12:28 PM, Anonymouse wrote:
On Wednesday, 14 December 2016 at 17:24:29 UTC, Anonymouse wrote:
The with keyword then?
bool equal(R1, R2)
with (std.range : isInputRange, isOutputRange) && (std.stdio :
writeln) && (std.algorithm)
if (isInputRange!R1 && isInputRange!R2)
{ ... }
I guess the &&s there don't make sense. Maybe with a semicolon delimeter
instead.
bool equal(R1, R2)
with (std.range : isInputRange, isOutputRange; std.stdio : writeln;
std.algorithm)
if (isInputRange!R1 && isInputRange!R2)
{ ... }
This would not pass either. -- Andrei
