On Thursday, 8 March 2018 at 16:19:40 UTC, Steven Schveighoffer
wrote:
On 3/8/18 10:27 AM, Markus wrote:
Hi
I got the following c++ code [lib.cpp]:
namespace ns_a
{
class class_a {
};
void some_function(class_a*) {;}
}
and the following d code [main.d]:
extern (C++, namespace_a) {
did you mean ns_a?
-Steve
yes, that's clearly the issue in my first post. :) I failed when
I made a minimal sample for this forum
[lib.cpp]:
namespace ns_a
{
class class_a {
};
void some_function(class_a*) {;}
}
[other.d]:
extern (C++, ns_a) {
class class_a {}
}
[main.d]:
import other;
extern (C++, ns_a) {
void some_function(class_a);
}
void main() {
class_a instance_a;
ns_a.some_function(instance_a);
}
compilation:
g++ -shared lib.cpp -o libissue.so
dmd main.d -L-lissue -L-L.
error:
main.o: In function `_Dmain':
main.d:(.text._Dmain[_Dmain]+0xa): undefined reference to
`ns_a::some_function(ns_a::class_a*)'
collect2: error: ld returned 1 exit status
Error: linker exited with status 1
symbols:
nm --demangle libissue.so | some_function
000000000000059a T ns_a::some_function(ns_a::class_a*)
It doesn't seem like an error, but it is.
I still don't get it, whey I'm not allowed to split the namespace
declarations.
