On 03/10/18 16:56, Stanislav Blinov wrote:
struct S {
this(S rhs);
OMG, that's so simple!!! Why didn't I think of it?
Oh wait, I did.
And this simply and utterly doesn't work.
If you read the DIP, you will notice that the *address* in which the old
instance resides is quite important for performing the actual move. This
is not available with the interface you're suggesting, mainly because by
the time you have rhs, it has already moved.
In other words, for the interface above to work, the type must already
be movable, which kinda contradict what we're trying to achieve here.
in C++ would have an equivalent signature of
ReturnType foo(Type&& x); // NOT ReturnType foo(Type x);
No, it is not. You see, in C++, x is an "rvalue *reference*". x has not
moved by this point in the run, it has simply had its address passed to
foo. Please see
https://stackoverflow.com/questions/28483250/rvalue-reference-is-treated-as-an-lvalue
Shachar
