Andrei Alexandrescu <seewebsiteforem...@erdani.org> wrote
max of n elements is O(n).
T max( T )( T[] values ) {
T result = values[0];
foreach ( i, e; values[1..$] ) {
if ( max( values[i+1..$] ) > result ) {
result = max( values[i+1..$] );
}
}
return result;
}
--
Simen
