Steven Schveighoffer, el 29 de junio a las 08:13 me escribiste: > >>There is one thing that bugs me about this solution though. What if the > >>user does this: > >>(1) Grab the pointer. *ptr = prop; > >(1) Grab the pointer. T* ptr = ∝ > > > >>(2) assigns to it. *ptr = val; > >>(3) expects the result to be updated in prop. assert(val == prop); > > > > Why would this assert fail? If a property returns a ref
What if it doesn't? If returns a temporary calculated value? > then you > set through that ref. What you did is no different, you just > delayed the assignment for a bit. > > You can reduce your test case to: > > (1) assign to the property. prop = val; Is not the same at all! prop = val will call the setter function, *ptr = val will not! -- Leandro Lucarella (AKA luca) http://llucax.com.ar/ ---------------------------------------------------------------------- GPG Key: 5F5A8D05 (F8CD F9A7 BF00 5431 4145 104C 949E BFB6 5F5A 8D05) ---------------------------------------------------------------------- ¿Qué será lo que hace que una brújula siempre marque el norte? - Ser aguja, nada más, y cumplir su misión. -- Ricardo Vaporeso