Dnia 24-07-2010 o 12:52:51 Tomek Sowiński <j...@ask.me> napisał(a):
Funny enough, if you put Bar into Foo (Foo bar = new Bar; ) it doesn't work no more.
Eh, not funny at all. It doesn't work because it shouldn't (I think).
Dnia 24-07-2010 o 12:52:51 Tomek Sowiński <j...@ask.me> napisał(a):
Funny enough, if you put Bar into Foo (Foo bar = new Bar; ) it doesn't work no more.
Eh, not funny at all. It doesn't work because it shouldn't (I think).