On Fri, 01 Oct 2010 19:36:11 +0400, Trass3r <[email protected]> wrote:
void main()
{
Baz baz = new Baz();
Bar bar = baz;
Foo foo1 = bar;
Foo foo2 = baz;
assert(foo1 is foo2);
}
foo1 and foo2 have the same type and point to the same object. Yet they
have different addresses. Is it a bug, or a feature?
Looks fine?! Isn't foo1 == foo2 what you want?
Sadly, opEquals is only defined for Objects, not interfaces:
Error: function object.opEquals (Object lhs, Object rhs) is not callable
using argument types (Foo,Foo)
Besides, I put `is' on purpose. With that assertion I make sure that
references are *same*, not that they are equal.
