On Tue, 12 Oct 2010 17:08:16 -0400, Peter Alexander
<peter.alexander...@gmail.com> wrote:
In short, when UFC is working on all types, will this be possible:
Foo opBinary(string op)(Foo a, Foo b)
{
return ...;
}
Foo x, y;
Foo z = x + y;
My reasoning here is that x + y is supposedly sugar for
x.opBinary!("+")(y), so the free opBinary defined above could be chosen
as a pseudo member of Foo.
Will this be possible?
Unknown, but unlikely given how UFC for arrays work today: neither
operator overloads nor templates are supported.
