On 10/19/2010 05:44, Don wrote: > Rainer Deyke wrote: >> Simple. If the template is in a library file, it's library code, >> regardless of where it was instantiated. > > The separation isn't clean. User code instantiates library code which > instantiates user code. Look at std.algorithm, for example. > Mixins and template alias parameters blur things even further.
There are exactly four possible situations: - Template in library code instantiated by library code. - Template in library code instantiated by user code. - Template in user code instantiated by library code. - Template in user code instantiated by user code. These cases can be nested arbitrarily deep, but that doesn't add additional cases. If we categorically ignore where a template is instantiated, the four cases reduce to just two: - Template in library code. - Template in user code. -- Rainer Deyke - rain...@eldwood.com
