On Jun 17, 11 15:32, Walter Bright wrote:
On 6/16/2011 11:59 PM, Kagamin wrote:I mean that function pointers are not documented to allow dereference operator, that's why behavior of your code is implementation-dependent. You spend too much time writing in C++.I don't know what you mean.
You should call the function pointer as
return fp(x);
not
return (*fp)(x);
