On 2011-10-05 03:49, Robert Jacques wrote:
On Tue, 04 Oct 2011 12:54:27 -0400, Jacob Carlborg <d...@me.com> wrote:
On 2011-10-04 17:14, Robert Jacques wrote:
I'm sorry, you're right. In my mind b extended to the end of the a
array, for some reason. However, if you do define b to extend to the end
of the a array, then it can append without allocating:
auto a = [0, 1, 2, 3, 4];
auto b = a[2 .. $];
b ~= 5;
assert(b[0]==2);
a[2] = 10;
assert(b[0]==10);
So please don't dismiss this point.
Hmm, D1 and D2 behaves differently in this case. In D1 "a" is not
changed when "b" is changed. Since you append to "b" I though that it
would always require a reallocation of "b".
Appending has never mandated reallocation. Maybe you're confusing it
with concatenation (i.e. b = b ~ 5;), which does always reallocate. Or
the period in time when the anti-array-stomping parts of druntime was
overly conservative and would have prevented b from appending in place.
Yeah, maybe you're right.
--
/Jacob Carlborg
