Sure, and hijacking is bound to happen under your proposal, no? How would it be detected?
On 22 October 2011 06:51, Robert Jacques <sandf...@jhu.edu> wrote: > On Fri, 21 Oct 2011 19:04:43 -0400, Manu <turkey...@gmail.com> wrote: > >> It would still allow function hijacking. >> void func(double v); exists... >> func(2); >> then someone comes along and adds func(float v); .. It will now hijack the >> call. >> That's what you mean right? >> > > Hijacking is what happends when someone adds func(float v); _in another > module_. And that hijack would/should still be detected, etc. like any > other hijack. >
