Hello,
I have a question concerning threading. I use Visual Studio with the Visual-D
plugin. The problem is somehow that when executing the code below "Derived
thread running." is displayed 3 times on the console but not before "return 0"
is reached. Then "Derived thread running." is displayed 3x all of a sudden, but
not each one by one after each other. This looks a bit strange to me.
When I unquote the Thread.sleeps after every d?.start() "Derived thread
running." is displayed immediately on the console when stepping over
Thread.sleep with the debugger. When stepping over d*.start() still nothing
happens regardless how much time I wait in the debugger till I jump to the next
line. I can't make really head or tail of this. I would expect "Derived thread
running." to appear on the console somewhen after d?.start() was executed.
Thereafter I could do an additional Thread.sleep if I wanted to. But this would
not be necessary for any "Derived thread running." message to be displayed on
the console.
I believe there is something with the debugger I don't understand or don't
realize. Any suggestions/ideas?
Thank you, Oliver Plow
import std.stdio, core.thread;
import DerivedThread;
int main(string[] argv)
{
DerivedThread dt1 = new DerivedThread();
dt1.start();
// Thread.sleep(dur!("seconds")( 1 ));
DerivedThread dt2 = new DerivedThread();
dt2.start();
// Thread.sleep(dur!("seconds")( 1 ));
DerivedThread dt3 = new DerivedThread();
dt3.start();
// Thread.sleep(dur!("seconds")( 1 ));
Thread.sleep(dur!("seconds")( 4 ));
return 0;
}
------------------ DerivedThread.d ------------------
import std.stdio, core.thread;
class DerivedThread : Thread {
this() {
super( &run );
}
private :
void run() {
writeln("Derived thread running.");
}
}
--
Empfehlen Sie GMX DSL Ihren Freunden und Bekannten und wir
belohnen Sie mit bis zu 50,- Euro! https://freundschaftswerbung.gmx.de
