Re: Inheritance of purity

[Timon Gehr]

On 02/25/2012 10:28 PM, deadalnix wrote:

Le 25/02/2012 21:44, Walter Bright a écrit :

On 2/25/2012 9:53 AM, deadalnix wrote:

And suddenly, the override doesn't override the same thing anymore.
Which is
unnacceptable.

class A {
void fun() const { }
void fun() { }
}

class B : A {
override void fun() { }
}

----

dmd -c foo
foo.d(6): Error: class foo.B use of foo.A.fun() hidden by B is deprecated

So, how do someone override the non const version of the function but
not the const version ?

By explicitly stating that he is aware of all the overloads:

class B : A {
    alias A.fun fun;
    override void fun() {  }
}

Alternatively:

class B : A{
    override void fun()const{super.fun();}
    override void fun() {  }
}