On Tuesday, 13 March 2012 at 22:30:02 UTC, Tobias Brandt wrote:
Fortran uses pass-by-ref by default. You could try

    integer, value :: i

in the Fortran function declaration, OR

    *int

in the MyHandler declaration.
in case integer, value :: i or integer, intent(in) :: i

same results


in case int*

int * i;
*i=5;
(*mh)(i);

object.Error: Access Violation
----------------
409960
4097D7
402BA8
402BE7
4027F7
413635
----------------


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