On 4 May 2012 11:46, Jonathan M Davis <jmdavisp...@gmx.com> wrote: > typeof(foo) blah2 = &func; >
I just spotted the problem: typeof(&foo) blah = &foo; Was missing the '&' before the type. This works... However, in my case, I don't have such a function defined to copy the type from, so it doesn't help me any :/
