On Wed, 30 May 2012 17:42:47 -0400, José Armando García Sancio
<jsan...@gmail.com> wrote:
On Wed, May 30, 2012 at 5:30 PM, Steven Schveighoffer
<schvei...@yahoo.com> wrote:
All deadlocks involving A and B mutexes. Or if not, can you show how?
I
can't see it.
-Steve
This can cause a deadlock because locking order is not guaranteed, no?
synchronized class A {
void delegate(B b) { b.call() }
void call() {}
}
synchronized class B {
void delegate(A a) { a.call() }
void call() {}
}
Thanks,
-Jose
PS. This may not compile not sure if it should be 'void
delegate(shared B b)', etc.
A and B are not modifiable. Given the implementation of A and B that I
gave, how can you achieve deadlock?
The big problem I see with allowing anyone to synchronize on A and B is
that one cannot achieve the property of "not possible to use me in a
deadlock."
-Steve
