On Friday, August 17, 2012 02:32:01 Mehrdad wrote: > > C++ makes no such guarantees, because you're free to cast away > > const and modifiy objects > > Not correct, as far as I understand. > C++ only lets you cast away _const references_ to _mutable_ > objects. > If the object happens to have been const _itself_, then that's > undefined behavior.
Well, then our understandings on the matter conflict, and I don't know for certain which of us is correct. - Jonathan M Davis
