On 08/27/2012 02:44 AM, Walter Bright wrote:
On 8/26/2012 4:50 PM, Timon Gehr wrote:
On 08/27/2012 12:41 AM, Walter Bright wrote:
The trouble for function pointers, is that any default args would need
to be part of the type, not the declaration.
They could be made part of the variable declaration.
You mean part of the function pointer variable?
Yes.
Consider what you do with a function pointer - you pass it to someone
else. That someone else gets it as a type, not a declaration.
If it is a template function, yes. But then you may as well pass the
function pointer variable per alias, which is common.
Otherwise someone else gets nothing but a parameter declaration.
I.e. you lose the default argument information, since that is not attached to
the
type.
I think most valid existing use cases would still be supported:
int execFunctionPointer(int function(int = 2) fun){
return fun();
}
auto dg = (int x, int y=2){ return x+y; }
writeln(range.map!dg());
int function(int=3)[] funs;
funs[0]();
It is up to you if it is worth the effort, of course.
