This is a little insane, but it works.
int Recurse(int a)
{
if (a <= 1)
return 1;
else
// can we replace explicit call to "Recurse"
// with "self" using a mixin or some other means?
// return a * Recurse(a - 1);
mixin("return a * mixin(__traits(identifier,
__traits(parent, {})))(a - 1);");
}
--rt
On Tuesday, 25 September 2012 at 04:42:43 UTC, Rob T wrote:
On Sunday, 23 September 2012 at 17:15:13 UTC, Ben Davis wrote:
Here's another one that might work, and be less error-prone:
mixin template Self() {
auto self = __traits(identifier, __traits(parent, {}));
}
void test() {
mixin Self;
writeln(self);
}
OK, we've managed to get the calling function symbol name
without re-specifying it. Now I wonder if we can perform mixin
magic to execute a function recursively without re-specifying
the function name?
Example recursive function
int Recurse(int a)
{
if (a <= 1)
return 1;
else
// can we replace explicit call to "Recurse"
// with "self" using a mixin or some other means?
return a * Recurse(a - 1);
}
We could try and get the function pointer, but that seems like
the wrong approach. I'd rather get the function name, do some
mixin magic with it to generate the compile time code that uses
the function name directly. Can we mixin a mixin???
--rt
