On 02/10/12 14:02, Andrej Mitrovic wrote:
On 10/2/12, Don Clugston <d...@nospam.com> wrote:
A proposal to clean up this mess
--------------------------------
Any compile-time value of type immutable(char)[] or const(char)[],
behaves a string literals currently do, and will have a \0 appended when
it is stored in the executable.
ie,
enum hello = ['H', 'e', 'l', 'l', 'o', '\n'];
printf(hello);
will work.
What about these, will these pass?:
enum string x = "foo";
assert(x.length == 3);
void test(string x) { assert(x.length == 3); }
test(x);
If these don't pass the proposal will break code.
Yes, they pass. The \0 is not included in the string length. It's
effectively in the data segment, not in the string.
