k = pmt.intern('spam')
nil = pmt.get_PMT_NIL()
v = pmt.dict_ref(d, k, nil)
The last argument to dict_ref is what gets returned if the key is not found.
On Fri, Jul 29, 2022 at 11:13 AM George Edwards <gedwards....@gmail.com>
wrote:
> Hello GNURadio Community,
>
> I am creating a Python OOT block to send/receive pmt list and pmt
> dictionary messages. In both cases, I am having problems extracting the
> elements in the message. Let's assume (some trivial values):
> P_list = pmt.to_pmt([1, 2, 3.45, 'eggs'])
> P_dict = pmt.to_pmt({'spam': 20, 'eggs': 40})
>
> How do I extract individual elements from P_list and P_dict? Nothing I
> tried worked.
>
> I appreciate any help.
>
> Regards,
> George
>
