Hi there,
my idea: I'll change the css() function, so you can supply the correct css
definition or the javascript attribute, i.e:
$().css("zIndex", "2")
And
$().css("z-index", "2")
will do the same. This is achieved by doing the following on the second
method:
1) First, try to read the attribute from DOMelement.z-index, if this returns
null, then
2) get the style string via DOMelement.getAttribute("style"), which returns
the proper css definitions,
3) split into array via split(";")
4) if z-index is found, change it and merge the array again, then do
setAttribute("style", mergedArray)
5) if z-index is not found, add it to the array, merge it and to the same.
Cool or not?
Paul
-----Ursprüngliche Nachricht-----
Von: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Im
Auftrag von Michael Geary
Gesendet: Mittwoch, 6. September 2006 20:41
An: 'jQuery Discussion.'
Betreff: Re: [jQuery] Bug with .css('z-index', '2')
> > From: Dylan Verheul
> > Actually, in DOM terms, zIndex is the only correct name.
> From: aedmonds
> Right... but for CSS properties I believe z-index is the only correct
> name for the zIndex property. Maybe I'm wrong but do know you set
> zIndex by using
>
> p { z-index: 2; }
>
> I guess I've really never tried
>
> p { zIndex: 2; }
Nor would you want to.
It's always names-like-this in CSS code and namesLikeThis in the DOM.
-Mike
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