> I believe that jQuery has a sort of built in queue in that effects are > chainable. So you'd simply write all of the effects in one long chain and > each of them would happen in the order you specify in your chain.
Exactly, so doing:
$("#foo").slideDown('slow').slideUp('slow');
will be queued completely.
--John
_______________________________________________
jQuery mailing list
discuss@jquery.com
http://jquery.com/discuss/
