$(function() {
$('[EMAIL PROTECTED]').click(function() {
this.wasChecked = this.checked;
});
function move(from, to) {
return function() {
$(from + ' input').appendTo(to);
$(to + ' [EMAIL PROTECTED]').each(function() {
this.checked = this.wasChecked;
});
}
}
$('#btn').toggle(move('#d1', '#d2'), move('#d2', '#d1'));
});
On 10/12/06, Klaus Hartl <[EMAIL PROTECTED]> wrote:
Todd Menier schrieb:
> Hello,
> The following test code moves 2 form elements from one location in the
> DOM to another. Both elements retain their state just fine in FireFox,
> but in IE the current state of the checkbox is lost when the element is
> moved:
>
> <script>
> $(function() {
> $('#btn').toggle(
> function() {$('#d1 input').appendTo('#d2');},
> function() {$('#d2 input').appendTo('#d1');}
> );
> });
> </script>
>
> <button id="btn">move</button>
> <div id="d1">1:<input type="checkbox"/><input type="text"/></div>
> <div id="d2">2:</div>
>
> Is there a "preferred" way to deal with this in jQuery? I can think of a
> number of ways to deal with it, but I would imagine this is a very
> common scenario, so I thought I'd ping the group before proceeding with
> my hack. :-)
>
Not sure, but I think it's nearly impossible to be handled by jQuery
without much overhead, so this should be regarded as an IE bug to work
around...:
$(function() {
$('#btn').toggle(
function() {
var jqInput = $('#d1 input');
var checked = jqInput[0].checked;
jqInput.appendTo('#d2')[0].checked = checked;
},
function() {
...
}
);
});
-- Klaus
_______________________________________________
jQuery mailing list
discuss@jquery.com
http://jquery.com/discuss/
_______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/
