Chris, Either Yehuda or my solution will work for you.
Take a look at http://docs.jquery.com/DOM/Traversing/Selectors#Custom_Selectors_2 for more info about the :first selector. To use your example: $('#foo').parents('tr:first') or $('#foo').parents('tr').eq(0) Karl Rudd On 1/16/07, Chris Domigan <[EMAIL PROTECTED]> wrote: > Matt - I want the first ancestor of a certain type, not the first parent. > > Yehuda - won't this just select all tr's that are the first tr's in their > table? > > To clarify, say I have this structure: > > <table> > <tr> > <td> > <table> > <tr> > <td> > <a id="foo">Demo</a> > </td> > </tr> > </table> > </td> > </tr> > </table> > > I want to select the first <tr> it comes to while searching upwards (or > outwards). > > Chris > > _______________________________________________ > jQuery mailing list > discuss@jquery.com > http://jquery.com/discuss/ > > > _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/
