FYI, According to the docs, MySQL 5.0 supports the COALESCE() function.
 Also, you don't need to pass the null in the function (it defaults to null
if all the values are null).

http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html#function_coalesce


-Nelson


On Mon, Apr 9, 2012 at 12:53 PM, Tepfer, Seth <la...@emory.edu> wrote:

>  Nathan reminded me I didn’t give full info:****
>
> **·         **Small data set <1K records****
>
> **·         **Using MySQL 5.0****
>
> ** **
>
> Sure, I have a working answer with query1 (students with Temp or Perm),
> query2 (all students except those returned in Q1), Union Q1 + Q2.****
>
> ** **
>
> But There has to be a more efficient method. I know with our servers and
> the recordset, the need for efficiency is minimal, but I don’t want to be
> lazy or miss a chance to learn new techniques. ****
>
> ** **
>
> Isn’t MySQL faster than CF at doing the select? If I can do it all in one
> call, isn’t it better to make MySQL do the heavy lifting?****
>
> ** **
>
> *From:* ad...@acfug.org [mailto:ad...@acfug.org] *On Behalf Of *Charlie
> Arehart
> *Sent:* Monday, April 09, 2012 11:01 AM
> *To:* discussion@acfug.org
> *Subject:* RE: [ACFUG Discuss] Tricky SQL help?****
>
> ** **
>
> Just a guess, with the limited info, but it seems to me that you’d just
> want then for the query to get “all the students”, and make the decision as
> to what address to “show” in CFML while looping over the results. Or do you
> have some reason to want to do this all in a query?****
>
> ** **
>
> /charlie****
>
> ** **
>
> *From:* ad...@acfug.org [mailto:ad...@acfug.org <ad...@acfug.org>] *On
> Behalf Of *Tepfer, Seth
> *Sent:* Monday, April 09, 2012 10:45 AM
> *To:* discussion@acfug.org
> *Subject:* [ACFUG Discuss] Tricky SQL help?****
>
> ** **
>
> I know this is not strictly a CF issue, but I’m trying to find the most
> efficient way of doing this, and a single query seems faster than 2 queries
> plus a query of queries.****
>
>  ****
>
>  ****
>
> I have two tables, one of student names, one of addresses. ** **
>
>  ****
>
> *Students*: id, name, emplID****
>
> *Addresses*: emplID, addressType, addressline1, city, state, ****
>
>  ****
>
> *Student table data:*****
>
> 1, john dooley, 1234567****
>
> 2, jane dooley, 2345678****
>
> 3, tom dooley, 33456780****
>
>  ****
>
> *Addresses table data:*****
>
> 1234567, onCampus, 101 Dowman, null, null****
>
> 1234567, home address, 100 main street, springfield, IL****
>
> 1234567, permanent forward, 120 main street, Atlanta, GA****
>
> 2345678, home address, 200 main street, springfield, MO****
>
> 2345678, temporary forward, 130 main street, Atlanta, GA****
>
> 3456789, home address, 300 main street, springfield, GA****
>
>  ****
>
> Every student has a home address. Some have permanent or temporary
> forwards. The query results I want to return are ****
>
> ·         All the student names****
>
> ·         If they have permanent or temporary forward, that address****
>
> ·         If they do not, a null for the address (NOT the home address or
> onCampus address)****
>
>  ****
>
> I’ve tried an outer join with a ‘where addressType = ‘permanent or
> temporary’, but that doesn’t give me all the names, just the ones with a
> forward. ****
>
> Thanks for any time you can give.****
>
>  ****
>
> ** **
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