On Mon, 23 Mar 2009, Yanchun Wang wrote:
Hi:
Thank for your answer.But I have another question.
"GNU make" can compile program in multithread by option "-j".
1) If "GNU make" calls GCC when multithread compiling, does "GNU make"
know that GCC is placed by distcc?
2) In other words, if I want to write a program like distcc, do I need to
hack "GNU make"
to make it know my program is a wrapper of GCC, and let "GNU make" to call
my wrapper
directly?
3) If "GNU make" does know any knowledge on distcc, how does it can call
distcc and give
every thread a command line instruction?
An example. I build a test package with the following command:
make -j32 CC=distcc
make will invoke distcc instead of gcc, and pass it the compiler
arguments from the makefile. With the -j option to make, many jobs are
running concurrently, but they are all distcc processes (until they
invoke gcc of course). GNU Make doesn't need to be modified for distcc to work.
Ian Baker
2009/3/23 <iba...@mail.cern.ch>
On Mon, 23 Mar 2009, Yanchun Wang wrote:
---------- Forwarded message ----------
From: Yanchun Wang <yanchun....@gmail.com>
Date: 2009/3/23
Subject: Re: [distcc] how to get separate compile tasks
To: DaNiMoTh <jjdanim...@gmail.com>
Hi:
If distcc's input is a makefile...
distcc's input isn't a makefile. Within the makefile, distcc is invoked as
a wrapper around gcc and as such intercepts and analyses the compiler
arguments.
Ian Baker
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