Oopsie:
On Thursday 28 February 2013, Shai Berger wrote:
>
> Note that with this suggestion:
>
> qset.filter(a=b).first(c)
>
> is not equivalent to
>
> qset.order_by(c).filter(a=b)
>
That should have read
qset.order_by(c).first(a=b)
Shai.
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