[Django] #23346: django.utils.functional.lazy picks the wrong method implementation

[Django]

#23346: django.utils.functional.lazy picks the wrong method implementation
-------------------------------+--------------------
     Reporter:  gavinwahl      |      Owner:  nobody
         Type:  Uncategorized  |     Status:  new
    Component:  Uncategorized  |    Version:  1.6
     Severity:  Normal         |   Keywords:
 Triage Stage:  Unreviewed     |  Has patch:  0
Easy pickings:  0              |      UI/UX:  0
-------------------------------+--------------------
 When a subclass of resultclasses is returned by the wrapped function,
 method implementaions are looked up on the base class (the one in
 resultclasses), not on the object actually returned.

 {{{
 #!python
     def test_lazy_base_class_override(self):
         """Test that lazy finds the correct (overridden) method
 implementation"""

         class Base(object):
             def method(self):
                 return 'Base'

         class Klazz(Base):
             def method(self):
                 return 'Klazz'

         t = lazy(lambda: Klazz(), Base)()
         self.assertEqual(t.method(), 'Klazz')
 }}}

 In the current implementation, `Base.method` will be called, not
 `Klazz.method`.

-- 
Ticket URL: <https://code.djangoproject.com/ticket/23346>
Django <https://code.djangoproject.com/>
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