#35395: Python 3.12 filter bug with Django 4.2.11 ---------------------------------+-------------------------------------- Reporter: Tim Richardson | Owner: nobody Type: Bug | Status: new Component: Template system | Version: 4.2 Severity: Normal | Resolution: Keywords: | Triage Stage: Unreviewed Has patch: 0 | Needs documentation: 0 Needs tests: 0 | Patch needs improvement: 0 Easy pickings: 0 | UI/UX: 0 ---------------------------------+-------------------------------------- Description changed by Tim Richardson:
Old description: > I have a template with a fragment like this: > > <span > class="fs-6">Supplier: {{ > po_metadata|get_item:dict_item.PONumber|get_item:"supplier" }} PO Date: > {{ po_metadata|get_item:dict_item.PONumber|get_item:"order_date" | > slice:":10" }} </span> > > When using python 3.13.2, I get an exception in > django/template/defaultfilters.py slice_filter() > > This code does throw an exception with 3.11 > > The exception is a Key Error and it happens because instead a list being > passed to the filter, a dictionary is. An empty dict in my case. > > In python 3.11, the breakpoints in slice_filter() are not hit. Somehow > the preceeding filters are behaving differently in case of po_metadata > being an empty dict. New description: I have a template with a fragment like this: <span class="fs-6">Supplier: {{ po_metadata|get_item:dict_item.PONumber|get_item:"supplier" }} PO Date: {{ po_metadata|get_item:dict_item.PONumber|get_item:"order_date" | slice:":10" }} </span> When using python 3.13.2, I get an exception in django/template/defaultfilters.py slice_filter() This code does not throw an exception with 3.11 The exception is a Key Error and it happens because instead a list being passed to the filter, a dictionary is. An empty dict in my case. In python 3.11, the breakpoints in slice_filter() are not hit. Somehow the preceeding filters are behaving differently in case of po_metadata being an empty dict. -- -- Ticket URL: <https://code.djangoproject.com/ticket/35395#comment:1> Django <https://code.djangoproject.com/> The Web framework for perfectionists with deadlines. -- You received this message because you are subscribed to the Google Groups "Django updates" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-updates+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-updates/0107018f04ee5484-4330caf2-817e-40b0-9aa6-6c09828e3e94-000000%40eu-central-1.amazonses.com.