Hi all,

I'm currently developing a little django application for monitoring 
workstations. Each monitored host reports its own data by creating an object 
in django db. It can obviously occur that several workstations try to access 
the db at the same time. And I commonly get the following error (using the 
SQLite backend):

Traceback (most recent call last):
  File "/home/lw/localWatch/collect/collect.py", line 168, in ?
    h.save()
  File "/home/lw/django/django/db/models/base.py", line 166, in save
    db_values + [pk_val])
  File "/home/lw/django/django/db/backends/util.py", line 12, in execute
    return self.cursor.execute(sql, params)
  File "/home/lw/django/django/db/backends/sqlite3/base.py", line 69, in 
execute
    return Database.Cursor.execute(self, query, params)
pysqlite2.dbapi2.OperationalError: unable to open database file

When I manually launch my application, on only one host, there's no error, and 
the script correctly completes.

I thought that SQLite gracefully handled concurrent accesses, so I wonder why 
I get these errors. Is there a way to tune framework locks on the database, 
to change retry limits, or something else, to avoid this?

Thanks in advance,
-- 
Kilian CAVALOTTI                      Administrateur réseaux et systèmes
UPMC / CNRS - LIP6 (C870)
8, rue du Capitaine Scott                          Tel. : 01 44 27 88 54
75015 Paris - France                               Fax. : 01 44 27 70 00
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From: Kilian CAVALOTTI <[EMAIL PROTECTED]>
Organization: LIP6
To: django-users@googlegroups.com
Subject: SQLite concurrent access to database
Date: Sun, 21 May 2006 18:25:01 +0200
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Hi all,

I'm currently developing a little django application for monitoring 
workstations. Each monitored host reports its own data by creating an object 
in django db. It can obviously occur that several workstations try to access 
the db at the same time. And I commonly get the following error (using the 
SQLite backend):

Traceback (most recent call last):
  File "/home/lw/localWatch/collect/collect.py", line 168, in ?
    h.save()
  File "/home/lw/django/django/db/models/base.py", line 166, in save
    db_values + [pk_val])
  File "/home/lw/django/django/db/backends/util.py", line 12, in execute
    return self.cursor.execute(sql, params)
  File "/home/lw/django/django/db/backends/sqlite3/base.py", line 69, in 
execute
    return Database.Cursor.execute(self, query, params)
pysqlite2.dbapi2.OperationalError: unable to open database file

When I manually launch my application, on only one host, there's no error, and 
the script correctly completes.

I thought that SQLite gracefully handled concurrent accesses, so I wonder why 
I get these errors. Is there a way to tune framework locks on the database, 
to change retry limits, or something else, to avoid this?

Thanks in advance,
-- 
Kilian CAVALOTTI                      Administrateur réseaux et systèmes
UPMC / CNRS - LIP6 (C870)
8, rue du Capitaine Scott                          Tel. : 01 44 27 88 54
75015 Paris - France                               Fax. : 01 44 27 70 00

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