On Wednesday 14 June 2006 16:41, Guillermo Fernandez Castellanos wrote: > I've been developping a link model (see at the end of the post, kind > of personal delicious) , and when I try to use the admin interface to > add a url, I obtain the following error: > Request Method: GET > Request URL: http://127.0.0.1:8000/admin/links/link/ > Exception Type: OperationalError > Exception Value: no such column: links_link.link > Exception Location: c:\program > files\python24\lib\site-packages\django-0.91-py2.4.egg\django\db\back >ends\sqlite3\base.py in execute, line 69 > > It is really curious because the table seems to exist.
Does the column exist too? > Another question, I've developped a quick tag model (see also at the > end). Would I be able to use the same tag model for, say, blog posts > and images at the same time? Or would I have to subclass or use > different implementation of the Tag class? Given your implementation, you could use the Tag class with as many other models as you like. However, if your Tag class had a ForeignKey to a specific model, the common way to handle this is described here: http://feh.holsman.net/articles/2006/06/03/django-contenttype Luke -- "Adversity: That which does not kill me only postpones the inevitable." (despair.com) Luke Plant || L.Plant.98 (at) cantab.net || http://lukeplant.me.uk/ --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~----------~----~----~----~------~----~------~--~---
