On Mon, May 24, 2010 at 2:38 AM, ravi krishna <ravi.9...@gmail.com> wrote:
> This is the error i get now
>
> InvalidURL at /index
>
> nonnumeric port:
>
>
>
Note httplib is part of base Python, not Django. Therefore you will likely
find more expertise and help with using it on a Python list than here.
(Further the error you are reporting getting is when you are trying to
retrieve content from www.python.org; there will likely not be many on this
list who can help with www.python.org responding oddly.) For what it is
worth, the code you show works fine and retrieves what looks to be valid
content when I try it:
Python 2.5.2 (r252:60911, Jan 20 2010, 23:16:55)
[GCC 4.3.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import httplib
>>> conn=httplib.HTTPConnection("www.python.org")
>>> conn.request("GET", "/index.html")
>>> r1 = conn.getresponse()
>>> print r1.status, r1.reason
200 OK
>>> data1 = r1.read()
>>> len(data1)
17907
>>> data1[:200]
'<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd
">\n\n\n<html xmlns="http://www.w3.org/1999/xhtml"; xml:lang="en"
lang="en">\n\n<head>\n'
>>> conn.close()
>>>
Karen
--
http://tracey.org/kmt/
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