Typo...
The correct syntax is :
obj_list = [ i for i in MyObject.objects.all() if my_filter(i) ]
On Jun 5, 4:29 pm, johan de taeye <johan.de.ta...@gmail.com> wrote:
> Possible through basic Python:
>
> obj_list = [ i for i in MyObject.objects.all() where my_filter(i) ]
>
> Note that this filtering is happening on the Python side of things,
> whereas a queryset filter is executed in SQL on the database. The
> filtering on the database is normally much, much faster, so be careful
> with the python-style filtering...
>
> Johan
>
> On Jun 5, 12:32 pm, Joakim Hove <joakim.h...@gmail.com> wrote:
>
>
>
> > Hello,
>
> > I have a query list which I want to filter based on a computation
> > which I supply:
>
> > # Create a query set containing everything:
> > obj_list = MyObject.objects.all()
>
> > # Now - select only the element which pass some test:
> > obj_list = obj_list.filter( my_filter )
>
> > def my_filter( obj ):
> > # Does a computation based on obj values, and returns true or
> > false
> > ....
> > return true|false
>
> > Is something like this doable?
>
> > Joakim- Hide quoted text -
>
> - Show quoted text -
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-us...@googlegroups.com.
To unsubscribe from this group, send email to
django-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en.
