Yes! Thank you! I just used the (.+) for now, it's working.
On Jun 6, 7:23 pm, James Gregory <james....@gmail.com> wrote:
> or, if there's nothing that comes beneath brewery, just (r'^brewery/(.
> +)
>
> On Jun 7, 3:17 am, James Gregory <james....@gmail.com> wrote:
>
>
>
> > The regex class "\w" doesn't include spaces, so maybe you need
> > (r'^brewery/([\w ]+). Then again spaces in urls are represented as
> > "%20", so maybe you need (r'^brewery/([\w%]+), can't be bothered to
> > test right now. Or maybe I'm totally wrong.
>
> > James
>
> > On Jun 7, 3:05 am, joelklabo <joelkl...@gmail.com> wrote:
>
> > > bumping this, I'm still at a loss...
>
> > > On Jun 5, 1:28 pm, joelklabo <joelkl...@gmail.com> wrote:
>
> > > > I am trying to capture the slug from a URL to search and find the
> > > > object with that slug. Here is my URLconf:
>
> > > > (r'^brewery/(\w+)', breweryDetail),
>
> > > > It works when there are no spaces in the slug, but nothing comes up
> > > > when there are. There are no errors just no results showing up.
> > > > Here is my view code:
>
> > > > def breweryDetail(request, brewerySlug):
> > > > brews = Brew.objects.filter(brewerySlug__exact=brewerySlug)
> > > > return render_to_response('brewery_detail.html', {'brews':
> > > > brews})
>
> > > > Anyone have any ideas?
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