Hi

Is there anybody who has implemented jqqrid 3.7 with json and made it
work?.

I keep getting an error from FF

Error: uncaught exception: jqGrid - No such method: navGrid


<script src="http://127.0.0.1:8000/static/jquery/js/
jquery-1.4.2.min.js"></src </script>
<script src="http://127.0.0.1:8000/static/jquery/js/jquery-
ui-1.8.2.custom.min.js"></src </script>
<link rel="stylesheet" type="text/css" media="screen" href="http://
127.0.0.1:8000/static/jquery/css/dark-hive/jquery-
ui-1.8.2.custom.css" />
<link rel="stylesheet" type="text/css" media="screen" href="http://
127.0.0.1:8000/static/jqgrid/css/ui.jqgrid.css" />
<script src="http://127.0.0.1:8000/static/jqgrid/js/i18n/grid.locale-
en.js" type="text/javascript"></script>
<script src="http://127.0.0.1:8000/static/jqgrid/js/
jquery.jqGrid.min.js" type="text/javascript"></script>
<script src="http://127.0.0.1:8000/static/jqgrid/src/grid.jqueryui.js";
type="text/javascript"></script>
<script src="http://127.0.0.1:8000/static/jqgrid/src/
ui.multiselect.js" type="text/javascript"></script>


js looks like this:

jQuery("#list2").jqGrid({ url:'/xhr_test', dataType: "json",

                         colNames:['Country Name', 'Country Code',
'Nationality Code','Added Date'],
                         colModel:[
 
{name:'countryname',index:'countryref', width:90},
 
{name:'countrycode',index:'countrycode', width:100},
 
{name:'nationalitycode',index:'nationalitycode', width:80,
align:"right"},
 
{name:'added_date',index:'added_date', width:80, align:"right"} ],
rowNum:10, rowList:[10,20,30], pager: '#pager2', sortname: 'id',
viewrecords: true, sortorder: "desc", caption:"JSON Example" });
 
jQuery("#list2").jqGrid('navGrid','#pager2',
{edit:false,add:false,del:false});

Regards

Bjørn

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