Never mind; I found: import json
def view(request): ... my_result = ... return HttpResponse(json.dumps(my_result), mimetype="application/json") On Wed, Jul 7, 2010 at 6:05 PM, Jonathan Hayward < christos.jonathan.hayw...@gmail.com> wrote: > I just tried: > > json_serializer.serialize(result, ensure_ascii = False, stream = response) > > where result was boolean. I got an error complaining that it was not > iterable, and http://docs.djangoproject.com/en/dev/topics/serialization/seems > to discuss serialization of querysets. > > In this case I can easily enough create JSON manually, but is there a > preferred way to take dicts, lists, strings, numbers, etc. and render a > structure as JSON? > > -- > → Jonathan Hayward, christos.jonathan.hayw...@gmail.com > → An Orthodox Christian author: theology, literature, et cetera. > → My award-winning collection is available for free reading online: > ☩ I invite you to visit my main site at http://JonathansCorner.com/ > -- → Jonathan Hayward, christos.jonathan.hayw...@gmail.com → An Orthodox Christian author: theology, literature, et cetera. → My award-winning collection is available for free reading online: ☩ I invite you to visit my main site at http://JonathansCorner.com/ -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.