I've solved translating a JavaScript function to python:

from math import *

RADIUS = 6371 #Earth's mean raadius in km

def distance(origin, destiny):
    (latitude1, longitude1) = (origin[0], origin[1])
    (latitude2, longitude2) = (destiny[0], destiny[1])

    dLat = radians(latitude1 - latitude2)
    dLong = radians(longitude1 - longitude2)

    # matter of faith
    a = sin(dLat/2) * sin(dLat/2) + cos(radians(latitude1)) *
cos(radians(latitude2)) * sin(dLong/2) * sin(dLong/2)
    c = 2 * atan2(sqrt(a), sqrt(1-a))

    return (RADIUS * c)

# a test
origin = (40.96312364002175, -5.661885738372803)
destiny = (40.96116097790996, -5.66283792257309)
print distance(origin, destiny)


2010/7/29 Alexandre González <agonzale...@gmail.com>

> I going to try it now, but the unique results that I obtain in google
> searching [1] gd2gcc is this thread :)
>
> [1]
> http://www.google.com/search?hl=en&safe=off&q=gd2gcc&aq=f&aqi=&aql=&oq=&gs_rfai=
>
>
> <http://www.google.com/search?hl=en&safe=off&q=gd2gcc&aq=f&aqi=&aql=&oq=&gs_rfai=>Did
> you make some mistake writting it?
>
> Thanks,
> Álex González
>
>
> On Wed, Jul 28, 2010 at 19:34, !!CONDORIOUS!! <condor.c...@gmail.com>wrote:
>
>> (lat , lon in radians)
>>
>> pt 1 = lat, lon, alt=0
>> pt 2 = lat, lon, alt=0
>>
>> p1_gcc = gd2gcc(p1)
>> p1_gcc = gd2gcc(p2)
>>
>> gd2gcc ( is a standard operation found on the itnernet)
>>
>> dis = sqrt(sum(pow(p1_gcc-p2-gcc, 2)))
>>
>> cheers,
>>
>> 2010/7/28 Alexandre González <agonzale...@gmail.com>:
>> > Hi! I'm using the Django GEOS API [1] in my project to see the distance
>> > between two users.
>> > I get the coordinates from google maps in latitude/longitude mode and I
>> need
>> > to calculate the distance between them. I'm testing with .distance()
>> method
>> > at GEOSGeometry but I receive a strange value.
>> > This is the result of one of my test:
>> > In [45]: Point(40.96312364002175,
>> > -5.661885738372803).distance(Point(40.96116097790996,
>> -5.66283792257309))
>> > Out[45]: 0.0021814438604553388
>> > In Google Maps Distance Calculator [2] I can see that the result is:
>> 0.145
>> > miles = 0.233 km = 0.126 nautical miles = 233 meters = 764.436 feet
>> > A friend told me on Google that perhaps I must calculate the distance in
>> > UTMs and the results surely is a lat/long distance. To test it I need
>> pygps
>> > that is a project not maintained to import
>> > LLtoUTMfrom from LatLongUTMconversion
>> > Any idea about this?
>> > [1] http://docs.djangoproject.com/en/dev/ref/contrib/gis/geos/
>> > [2]
>> http://www.daftlogic.com/projects-google-maps-distance-calculator.htm
>> >
>> > --
>> > Please, don't send me files with extensions: .doc, .docx, .xls, .xlsx,
>> .ppt
>> > and/or .pptx
>> > http://mirblu.com
>> >
>> > --
>> > You received this message because you are subscribed to the Google
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>> > To unsubscribe from this group, send email to
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>>
>>
>>
>> --
>> Condor
>> 310.951.1177
>> condor.c...@gmail.com
>>
>> :%s/war/peace/g
>>
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>>
>
>
> --
> Please, don't send me files with extensions: .doc, .docx, .xls, .xlsx, .ppt
> and/or .pptx
> http://mirblu.com
>



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