Thank you!

Does python's super really works the way like in the last option?

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Valentin Golev
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2010/10/19 Łukasz Rekucki <lreku...@gmail.com>:
> On 19 October 2010 19:06, Valentin Golev <v.go...@gmail.com> wrote:
>> Hello,
>>
>> I'm trying to start using new class based views from the trunk.
>>
>> I need to rewrite a view which is decorated
>> django.contrib.auth.decorators.login_required.
>>
>> How should I go with that?
> There are couple of options.
>
> 1) decorate the final view (for use in urls.py):
>
>   decorated_view = login_required(MyView.as_view)
>
> In this option, you lose the ability to subclass the decorated view.
>
> 2) decorate the dispatch method. You need to turn login_required into
> a method decorator first (Django should probably provide a tool for
> this). Here[1] is an example how to do this.
>
> class MyDecoratedView(MyView):
>
>   �...@on_method(login_required):
>    def dispatch(self, *args, **kwargs):
>        # do any extra stuff here
>        return super(MyDecoratedView, self).dispatch(*args, **kwargs)
>
> 3) Make a class decorator, that does the above, so you could do:
>
> @on_dispatch(login_required)
> class MyDecoratedView(MyView):
>    pass
>
>>
>> I was going to write something like LoginRequiredMixin, but I have no
>> idea how to do this. I need to run my code before .dispatch(), but I
>> also have to call the old dispatch, but since Mixin aren't inherited
>> from View, I can't just override method and use super().
>
> This is option #4. You can just do:
>
> class LoginRequiredMixin(object):
>
>    def dispatch(self, *args, **kwargs):
>        bound_dispatch = super(LoginRequired, self).dispatch
>        return login_required(bound_dispatch)(*args, **kwargs)
>
>
> [1]: http://www.toddreed.name/content/django-view-class/
>
> --
> Łukasz Rekucki
>
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