Ok the motive is for this reason. I have a table generator class that display an html table from the query set depending on the columns that you selected class TableGenerator(name,mapping,data):
def __init__(self,name,mapping,data): self._mapping = mapping self._name = name self._data = data def render_table(self): # pseudo code * iterate through the mapping construct the table header * iterate through self._data queryset and construct the columns for the table body based on the mapping -- mapping is a variable that holds the mapping of table header with the actual field name of the model attribute -- data is just the queryset object. so here I want to generate a table to display every attribute in project while also display the related fields of user.first_name and user.last_name concatenated. How can i refer to that field in my TableGenerator class using the mapping generically? On Oct 28, 3:27 pm, Jumpfroggy <rocketmonk...@gmail.com> wrote: > What's your motive? Are you worried about performance? > > If performance is not an issue, you can just do this: > > for project in Project.objects.all(): > print project.user.first_name + ' ' + project.user.last_namea > > This might speed things up: > > projects = Project.objects.all().select_related('user') > for project in projects: > print project.user.first_name + ' ' + project.user.last_namea > > If that's not fast enough, you may want to do something using .extra() > or .raw(). I'm not sure how to do this effeciently with .extra(). -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.